Bash Question

14 Oct 2004

      Hi Everyone,

I am working on a bash script, and currently looking at examples. I
came across something I'm not sure what it means: if (( $? )); , the
double quotes and the $? is what I don't get. In the script there is
no variable set for ? so kinda lost.

Possible info: Simply enclose the particular arithmetic expression
between a "$((" and a "))",
                     and bash will evaluate the expression.

And also anyone have recommendation of a good bash scripting book.

Learning the bash Shell, 2nd Edition?

Thanks,

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