Have you seen this!?! Burning saltwater

[Kelsay, Brian - Kansas City, MO]

The key would be releasing stored energy in the form of chemical or
molecular bonds.  I once got more energy out of a system than I put in,
if you consider that all I did was add water to Drano crystals.  A
chemical reaction occurred that created heat, lots of it (I used too
much Drano in Chem lab than I was supposed to when making lye soap).
The drain I poured that mixture down, in order to get rid of it before
it did something bad, smoked for a bit.  It never did back up again
though.

Brian
 

-----Original Message-----
From:  Billy Crook
Sent: Tuesday, September 11, 2007 3:47 PM

You can not get more energy out of a system than you put in to it.
There are NO exceptions, Get over it.  The best you can hope for is
100% efficiency, and that would still only be a hope.

On 9/11/07, Jon Pruente <jdpruente at gmail.com> wrote:
> On 9/11/07, Jonathan Hutchins <hutchins at tarcanfel.org> wrote:
> > The energy required for the RF input (that according to most of the
> > articles "breaks down" the salt water) is the question - does it
take more
> > energy to provide that RF than the "flame" produces - or than can be
> > recovered from the flame.  (Remember, a flame in itself isn't a very
useful
> > source of energy, and there are considerable losses converting it to
> > electricity or other useful forms.)
>
> From what I've seen elsewhere it does take more energy to produce the
> RF than is released by the reaction.  It seems to be basically super
> heating the water so that the hydrogen and oxygen split, then when the
> atoms leave the area being excited, they "burn" and come back together
> as water again, with a  net loss of energy from waste heat.
>
> Jon.