From: hasty@netcom.com (Amancio Hasty Jr) Subject: Re: 386bsd, linux: which runs more out of the box? Date: Tue, 23 Mar 1993 16:53:51 GMT
In article <CGD.93Mar23030821@erewhon.CS.Berkeley.EDU> cgd@erewhon.CS.Berkeley.EDU (Chris G. Demetriou) writes:
>In article <1993Mar23.085058.13670@serval.net.wsu.edu> hlu@luke.eecs.wsu.edu (HJ Lu) writes:
>>Linux can do POSIX, SYSV and most of BSD.
>
>however, consider this:
>
>for a while, the slogan went: "all the world's a vax (running BSD)".
>then, it more or less became: "all the world's a sun (running a
> BSD-derivative, if SunOS < 5.0)."
>
>
>so 386bsd will do most of posix, and basically all of BSD stuff.
>
>and i think that, at this stage of the game, except for GNU software
>(which tends to be fine-tuned per platform), you'll end up
>being able to compile things just as, if not more easily
>under 386bsd...
>
>
>and i'm not sure the problems you had w/386bsd's strtod, but they
>might be fixed now... (but i'm not a libc hacker, so... 8-)
>
>
>chris
>--
>Chris G. Demetriou cgd@cs.berkeley.edu
>
> MENTALLY CONTAMINATED and proud of it!
Well, here is strtod.c which works tested with interviews, tk/tcl,
P3D, rayshared-4.0, etc...
Enjoy,
Amancio
=======================begin to hack now===========================
#include <stdlib.h>
#include <stddef.h>
#include <ctype.h>
/*
* strtod.c --
*
* Source code for the "strtod" library procedure.
*
* Copyright 1988-1992 Regents of the University of California
* Permission to use, copy, modify, and distribute this
* software and its documentation for any purpose and without
* fee is hereby granted, provided that the above copyright
* notice appear in all copies. The University of California
* makes no representations about the suitability of this
* software for any purpose. It is provided "as is" without
* express or implied warranty.
*/
#ifndef TRUE
#define TRUE 1
#define FALSE 0
#endif
#ifndef NULL
#define NULL 0
#endif
static int maxExponent = 511; /* Largest possible base 10 exponent. Any
* exponent larger than this will already
* produce underflow or overflow, so there's
* no need to worry about additional digits.
*/
static double powersOf10[] = { /* Table giving binary powers of 10. Entry */
10., /* is 10^2^i. Used to convert decimal */
100., /* exponents into floating-point numbers. */
1.0e4,
1.0e8,
1.0e16,
1.0e32,
1.0e64,
1.0e128,
1.0e256
};
Received: xxq
*----------------------------------------------------------------------
*
* strtod --
*
* This procedure converts a floating-point number from an ASCII
* decimal representation to internal double-precision format.
*
* Results:
* The return value is the double-precision floating-point
* representation of the characters in string. If endPtr isn't
* NULL, then *endPtr is filled in with the address of the
* next character after the last one that was part of the
* floating-point number.
*
* Side effects:
* None.
*
*----------------------------------------------------------------------
*/
double
strtod(string, endPtr)
const char *string; /* A decimal ASCII floating-point number,
* optionally preceded by white space.
* Must have form "-I.FE-X", where I is the
* integer part of the mantissa, F is the
* fractional part of the mantissa, and X
* is the exponent. Either of the signs
* may be "+", "-", or omitted. Either I
* or F may be omitted, or both. The decimal
* point isn't necessary unless F is present.
* The "E" may actually be an "e". E and X
* may both be omitted (but not just one).
*/
char **endPtr; /* If non-NULL, store terminating character's
* address here. */
{
int sign, expSign = FALSE;
double fraction, dblExp, *d;
double tmp1, tmp2;
char *p, c;
int exp = 0; /* Exponent read from "EX" field. */
int fracExp = 0; /* Exponent that derives from the fractional
* part. Under normal circumstatnces, it is
* the negative of the number of digits in F.
* However, if I is very long, the last digits
* of I get dropped (otherwise a long I with a
* large negative exponent could cause an
* unnecessary overflow on I alone). In this
* case, fracExp is incremented one for each
* dropped digit.
*/
int mantSize; /* Number of digits in mantissa. */
int decPt; /* Number of mantissa digits BEFORE decimal
* point.
*/
char *pExp; /* Temporarily holds location of exponent
* in string.
*/
/*
* Strip off leading blanks and check for a sign.
*/
p = string;
while (isspace(*p)) {
p += 1;
}
if (*p == '-') {
sign = TRUE;
p += 1;
} else {
if (*p == '+') {
p += 1;
}
sign = FALSE;
}
/*
* Count the number of digits in the mantissa (including the decimal
* point), and also locate the decimal point.
*/
decPt = -1;
for (mantSize = 0; ; mantSize += 1)
{
c = *p;
if (!isdigit(c)) {
if ((c != '.') || (decPt >= 0)) {
break;
}
decPt = mantSize;
}
p += 1;
}
/*
* Now suck up the digits in the mantissa. Use two integers to
* collect 9 digits each (this is faster than using floating-point).
* If the mantissa has more than 18 digits, ignore the extras, since
* they can't affect the value anyway.
*/
pExp = p;
p -= mantSize;
if (decPt < 0) {
decPt = mantSize;
} else {
mantSize -= 1; /* One of the digits was the point. */
}
if (mantSize > 18) {
fracExp = decPt - 18;
mantSize = 18;
} else {
fracExp = decPt - mantSize;
}
if (mantSize == 0) {
fraction = 0.0;
p = string;
goto done;
} else {
int frac1, frac2;
frac1 = 0;
for ( ; mantSize > 9; mantSize -= 1)
{
c = *p;
p += 1;
if (c == '.') {
c = *p;
p += 1;
}
frac1 = 10*frac1 + (c - '0');
}
frac2 = 0;
for (; mantSize > 0; mantSize -= 1)
{
c = *p;
p += 1;
if (c == '.') {
c = *p;
p += 1;
}
frac2 = 10*frac2 + (c - '0');
}
tmp1 = frac1;
tmp2 = frac2;
/* fraction = (1.0e9 * frac1) + frac2; */
fraction = (1.0e9 * tmp1) + tmp2;
}
/*
* Skim off the exponent.
*/
p = pExp;
if ((*p == 'E') || (*p == 'e')) {
p += 1;
if (*p == '-') {
expSign = TRUE;
p += 1;
} else {
if (*p == '+') {
p += 1;
}
expSign = FALSE;
}
while (isdigit(*p)) {
exp = exp * 10 + (*p - '0');
p += 1;
}
}
if (expSign) {
exp = fracExp - exp;
} else {
exp = fracExp + exp;
}
/*
* Generate a floating-point number that represents the exponent.
* Do this by processing the exponent one bit at a time to combine
* many powers of 2 of 10. Then combine the exponent with the
* fraction.
*/
if (exp < 0) {
expSign = TRUE;
exp = -exp;
} else {
expSign = FALSE;
}
if (exp > maxExponent) {
exp = maxExponent;
}
dblExp = 1.0;
for (d = powersOf10; exp != 0; exp >>= 1, d += 1) {
if (exp & 01) {
dblExp *= *d;
}
}
if (expSign) {
fraction /= dblExp;
} else {
fraction *= dblExp;
}
done:
if (endPtr != NULL) {
*endPtr = p;
}
if (sign) {
return (-1.00 * fraction);
}
return fraction;
}
double
atof(ascii)
const char *ascii;
{
return(strtod(ascii, (char **)NULL));
}
-- This message brought to you by the letters X and S and the number 3 Amancio Hasty | Home: (415) 495-3046 | ftp-site depository of all my work: e-mail hasty@netcom.com | sunvis.rtpnc.epa.gov:/pub/386bsd/incoming